(y+1)(y-3)-y^2=13

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Solution for (y+1)(y-3)-y^2=13 equation:


Simplifying
(y + 1)(y + -3) + -1y2 = 13

Reorder the terms:
(1 + y)(y + -3) + -1y2 = 13

Reorder the terms:
(1 + y)(-3 + y) + -1y2 = 13

Multiply (1 + y) * (-3 + y)
(1(-3 + y) + y(-3 + y)) + -1y2 = 13
((-3 * 1 + y * 1) + y(-3 + y)) + -1y2 = 13
((-3 + 1y) + y(-3 + y)) + -1y2 = 13
(-3 + 1y + (-3 * y + y * y)) + -1y2 = 13
(-3 + 1y + (-3y + y2)) + -1y2 = 13

Combine like terms: 1y + -3y = -2y
(-3 + -2y + y2) + -1y2 = 13

Combine like terms: y2 + -1y2 = 0
-3 + -2y + 0 = 13
-3 + -2y = 13

Solving
-3 + -2y = 13

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -2y = 13 + 3

Combine like terms: -3 + 3 = 0
0 + -2y = 13 + 3
-2y = 13 + 3

Combine like terms: 13 + 3 = 16
-2y = 16

Divide each side by '-2'.
y = -8

Simplifying
y = -8

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